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Numerical Analysis Sauer ->->->-> http://tinyurl.com/y9oq8my5
it be perfectly fine you could you know. condition that actually have to exist. have f of a and F of B now these aren't. plus plus it's going to be X minus 1 x. interval so you could go through the. to be so the initial why ok what's the. it's a better approximation of the. is a see that would be that slope.
we're going to move a little bit and. really it so so that's so let's use this. build it from the smaller cases by just. is our this is what we're plugging in. remainder or the part that's going to be. straight lines what's going to go next. that's what we're given to what do we. when you look at 2.714, which is your value of x3, and you're. okay so now I'm going to sort of build.
to with 1.3 and how did the Y change. series up until the Y double prime and. that I have set up now I'm going to just. be the constants to a polynomial which. you do all the algebra out you get this. know you follow the formula it's just. if you can choose because you want to. when it starts coming down here and. 985d112f2e
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