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The structure of a compound can be derived from the infrared spectra of a compound as different types of bonds have its own characteristic stretching frequency. According to the spectra the IR stretching frequencies are as follows: Therefore, we can say that there is no aromatic stretching and no carbonyl group stretching.
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In this reaction, we have taken equal amount of both reactant cyclopentanone and furfural. So, in the presence of NaOH, we get enolate ion which attack on carbonyl group of cyclopentanone. Finally, the removal of water molecule leads to the formation of product A. Comment(0). Step 2 of 2. In this reaction, we have taken
(a) Draw structures of all the monosaccharides (hul would yield the same alditol as your D-hexose. (b) Draw structures of all the monosaccharides that would yield the same phenylosazone as your D-hexose. (c) Draw structures of all the alditols that would be obtained by reduction of all possible D-hexoses, and indicate
Access Operational Organic Chemistry 4th Edition Chapter 55 solutions now. Our solutions are written by Chegg experts so you can be assured of the highest quality!
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Assuming the unknown compound to be aldehyde or an alcohol the following test can be carried out for both to identify the unknown compound. 2,4-DNP test: First considering the unknown compound as benzaldehyde the reaction of benzaldehyde with 2,4-DNP would be as follows: Then, considering the unknown
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First we have to discuss about the mechanism of formation of 2-nitro-1, 3, 5-trimethyl benzene as follows: Step1: In this step 1, 3, 5-trimethyl benzene is reacted with Bromide ion in the presence of acetic acid and formed a carbocation intermediate as follows: Comment(0). Step 2 of 6. Step 2: In this step nitronium fluoroborate
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