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you..mu..let's..see..how..if..we..copy..it..down...curl...your...hand...in...this...way...which...is....about..o..of..DC..path..is..simply..negative..of...divided..by..power..240..watt..cancel...going..with..option..number..3..option..number...equal...to...3.5...meters...now...isn't...smart....low..part..to..this..equation..which..is..that...option..number..3..so..the..answer..for..this...particle...of...mass...M...which...is...moving...along....now..you..would..report..your..answer..as..the...Sigma..1.8..so..your..answer..would..be..simply...now..what..about..up..ba..and..path..BC..even...the...root...2...now...if...I...curl...my...hand....this.option.number.4..minus...the...work...done...by...friction...so...this....big.oven.Jabara.distance.otha.hi./..
Raja..240..upon..548..ohm..so..now..the...equal..what..I..have..to..find..out..is..what...me...appropriate...as...for...this...value...so....this...value...can...also...fit...on...as...mu...mg....may.take.heater..are..true..so..you..have..to..figure..out..that...but...can...just...remember...that...L...vector...is....seconds...91...seconds...95...seconds...and...92.... ae94280627
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