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Proof. Let S be a complete subspace of a metric space X. Let x ? S. Then there is a sequence (xn) in S which converges to x (in X). Hence (xn) is a. Cauchy sequence in S. Since S is complete, (xn) must converge to some point, say, y in S. By the uniqueness of limit, we must have x = y ? S. Hence. S = S, i.e. S is closed.
3 Complete Metric Spaces, Normed Vector Spaces and Banach. Spaces. 2. 3.1 The Least Upper Bound Principle . . . . . . . . . . . . . . . . 2. 3.2 Monotonic Sequences of Real Numbers . . . . . . . . . . . . . 2. 3.3 Upper and Lower Limits of Bounded Sequences of Real Numbers 3. 3.4 Convergence of Sequences in Euclidean Space .
In mathematical analysis, a metric space M is called complete (or a Cauchy space) if every Cauchy sequence of points in M has a limit that is also in M or, alternatively, if every Cauchy sequence in M converges in M. Intuitively, a space is complete if there are no "points missing" from it (inside or at the boundary). For instance
Cauchy Sequences and Complete Metric Spaces. Definition: A sequence {xn} in a metric space (X, d) is Cauchy if. ?? > 0 : ?n ? N : m,n>n ? d(xm,xn) < ?. Remark: Every convergent sequence is Cauchy. Proof: Let {xn} > x, let ? > 0, let n be such that n>n ? d(xn,x) < ?/2, and let m,n>n. Then d(xm,x) <. ?. 2 and d(xn,x) <.
complete if A as a metric subspace of (X, d) is complete, that is, if every. Cauchy sequence (xn) in A converges to a point in A. By the above example, not every metric space is complete; (0,1) with the standard metric is not complete. Theorem 8.3. The space R with the standard metric is complete. Theorem 8.3 is a
27 Jan 2012
6.2 Complete metric spaces. Definition 6.3. A metric space (X, ?) is said to be complete if every Cauchy sequence (xn) in (X, ?) converges to a limit ? ? X. There are incomplete metric spaces. If a metric space (X, ?) is not complete then it has Cauchy sequences that do not converge. This means, in a sense, that there are
Example 4: The space Rn with the usual (Euclidean) metric is complete. We haven't shown this yet, but we'll do so momentarily. Remark 1: Every Cauchy sequence in a metric space is bounded. Proof: Exercise. Remark 2: If a Cauchy sequence has a subsequence that converges to x, then the sequence converges to x.
7 Complete metric spaces and function spaces. 7.1 Completeness. Let (X,d) be a metric space. Definition 7.1. A sequence (xn)n?N in X is a Cauchy sequence if for any ? > 0, there is. N ? N such that n,m > N ? d(xn,xm) < ?. It is clear that any convergent sequence is a Cauchy sequence: if xn > x then d(xn,xm) ? d(xn,x)
1.2 Remark. Every convergent sequence is Cauchy, but the converse is not true. 1.3 Definition. We say that a metric space (X, d) is complete if every Cauchy sequence in X has a limit in X, i.e., every Cauchy sequence is convergent. 1.4 Example. Rn with the Euclidean metric is complete. One may then ask whether all metric
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