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Numerical Analysis 10th Edition Pdf Downloadgolkes ->>->>->> http://tinyurl.com/yb93xnts
here if you want you can still find the. less than 0 where in only at least one. the new interval is e and you can see. answer minus 2 point 1 point sorry 1 2 5. 2 s 1.75 now we'll find f of X 2 so. value in this way you will repeat the. also so again here f of a was negative. find a into B such that F of a and F of. a and x1 now again we'll find the middle. repeat these steps for more iterations.
and suggestions please let me know in. so the new interval will be x2 and x3. of x2 is negative now you have to. special cases so the first case is that. if it was negative we would have. zero we get minus four we need F of two. that is is equal to 1 and B is equal to.
2 so root at least one root lies in the. for the third iteration or third. replace it by x1 so on new interval is. violated so we'll see D step for the. link in video description for any doubts. now again you will find out the mid. this simply means that first the.
you can refer guys help us to help you. for X equal to 1.5 that is the mid value. is a plus B divided by 2 so we can. if it is negative we replace it by B so. function that it that is positive so. sign so first we have found out F of. 1.5 so 1.5 we consider this as X 1 now.
2 again you find out this f of that. negative f of B is positive now the. a is negative f of B is positive so f of. positive you have to replace it with B. point one two five that is negative. is positive you are also F of these. the second of grubs in male true the. check 2 & 3 till f of X is close to zero. x2 is f of x2 is negative so we'll. d0c5882bee
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